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A ring is suspended from a point S on its rim as shown in the figure. When displaced from equilibrium, it oscillates with time period of 2 seconds. The radius of the ring is (take g = π² )

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0.5 m

0.15 m

1.0 m

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Detailed Solution

$\begin{array}{l} T = 2 π \sqrt{\frac{ℓ}{g}} \Rightarrow 2 = 2 π \sqrt{\frac{2 r}{g}} \Rightarrow \frac{1}{π} = \sqrt{\frac{2 r}{g}} \\ \frac{1}{π^{2}} = \frac{2 r}{g} \Rightarrow 2 r = 1 \\ r = 1 / 2 m; r = 0 .5 m \end{array}$

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