Q.

A ring of mass m = 0.2kg is attached to one end of a spring of force constant 
k=100 N/m and natural length l = 10 cm. The ring is constrained to move on a rough vertical wire in the shape of an ellipse of major axis 24cm and minor axis 16cm with its centre at origin (O). Initially the ring is at top point A with other end of the spring being fixed to the origin. Normal reaction of the wire on the ring is zero at A. The ring is given a horizontal velocity V=10ms1 towards right at A so that it just reaches point B. Find the work done against friction (in J) on the ring as it moves from A to B.  (g=10m/s2)

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answer is 10.16.

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Detailed Solution

 Wf=(kf+Uf)(ki+Ui)
 =0+12K(2cm)2
 [12m(10)2+12K(2cm)2+mg(8cm)]
 =12×0.2×1000.2×10×0.08
 =100.16=10.16J

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