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A ring of radius 3m has charge density $λ$ . Electric potential at 4m from its centre on its axis is ___ $[k = \frac{1}{4 {πε}_{D}}]$

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$\frac{6}{5} πkλ$

$\frac{1}{5} πkλ$

$\frac{2}{5} πkλ$

$\frac{3}{5} πkλ$

answer is C.

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Detailed Solution

The electric potential is given by

$V = \frac{1}{4 {πε}_{o}} . \frac{λ . 2 π . 3}{\sqrt{3^{2} + 4^{2}}} = \frac{6}{5} λπk$

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