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Q.

A ring of uniform mass density having mass m=100 gm and radius R=50 cm is suspended by two strings PS and PT from the point P on y-axis in vertical plane. The ring is kept parallel to horizontal surface on x-z plane. Ring carries a current i=722amp as shown in the figure. There exist a magnetic field (B= 1 Tesla) along negative x-axis. The tension in the string PS is T1 and in the string PT is T2. Find the ratio T1T2. (It is given that θ=60)

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(Take  g=10m/s2)

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answer is 3.

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Detailed Solution

T1cos60+T2cos60=mg

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T1+T2=2mg.....(i)

Taking torque about ‘O’

(T2cos60)R+|μ×B|=(T1cos60)R......(ii)
on solving, we get T1T2=3

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