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Q.

A ring radius R having a linear charge density λ moves towards a solid imaginary sphere of radius R2,  so that centre of the ring passes through the centre of the sphere. The axis of the ring perpendicular to the line joining the centers of the ring and sphere. The maximum flux through the sphere in this process is  λπRnε0. Then the value of n=

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answer is 3.

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Detailed Solution

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θ=π3         ϕ=λ(Rπ3)0

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A ring radius R having a linear charge density λ moves towards a solid imaginary sphere of radius R2,  so that centre of the ring passes through the centre of the sphere. The axis of the ring perpendicular to the line joining the centers of the ring and sphere. The maximum flux through the sphere in this process is  λπRnε0. Then the value of n=