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A river is flowing due east with a speed 3 ${ms}^{- 1}$ . A swimmer can swim in still water at a speed of 4 ${ms}^{- 1}$ . If swimmer starts swimming due north, then the resultant velocity of the swimmer is

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3 ${ms}^{- 1}$

5 ${ms}^{- 1}$

7 ${ms}^{- 1}$

2 ${ms}^{- l}$

answer is B.

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Detailed Solution

Here, Velocity of water flowing in river, $v_{r}$ = 3 ${ms}^{- l}$
Velocity of swimmer in still water, $v_{s} = 4 {ms}^{- 1}$

From figure,
The resultant velocity of the swimmer is
$v = \sqrt{{v_{s}}^{2} + {v_{r}}^{2}} = \sqrt{{(4)}^{2} + {(3)}^{2}} = \sqrt{25} = 5 {ms}^{- 1}$

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