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A river is flowing from west to east with a speed. $5 {ms}^{- 1}$ . A swimmer can swim in still water at a speed of $10 {ms}^{- 1}$ . If he wants to start from point A on south bank and reach opposite point B on north bank, in what direction should he swim?

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$30^{\circ}$ east of north

$60^{\circ}$ east of north

$30^{\circ}$ west of north

$60^{\circ}$ west of north

answer is C.

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Detailed Solution

$\sin θ = \frac{V_{W}}{V_{B W}} = \frac{5}{10} = \frac{1}{2} \Rightarrow θ = 30^{\circ} W of N$

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