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A river is flowing towards east with a velocity of 5 m s^-1. The boat velocity is 10 m s^-1. The boat crosses the river by shortest path. Hence,

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Resultant velocity of boat is $5 \sqrt{2} {ms}^{- 1}$ .

The direction of boat's velocity is 30^o west of north

Resultant velocity is $5 \sqrt{3} {ms}^{- 1}$ .

The direction of boat's velocity is north-west.

answer is A, C.

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Detailed Solution

For angle $θ$ in west of north,

$\sin θ = \frac{5}{10} = 0 .5, i.e., θ = 30^{\circ}$

V_r = resultant velocity

$= \sqrt{(10^{2}) - (5)^{2}} = 5 \sqrt{3} {ms}^{- 1}$

So, options (1) and (3) are correct.

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