Q.

A river of width L is flowing with uniform velocity V0. A swimmer jumps in water at point A with speed of V0  relative to water. Swimmer crosses the river in such a way that the resultant velocity of swimmer is always perpendicular to the line joining swimmer and point C.  Point B is directly opposite to point A and point A, B and C are collinear. If swimmer crosses the river in time T0;  then the value of T0  will be?  (   secθdθ=ln(secθ+tanθ)+C)
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a

T0=LV0ln(4+13)

b

T0=LV0ln(2+13)

c

T0=LV0ln(2+3)

d

T0=LV0ln(4+3)

answer is B.

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Detailed Solution

2L.dθ=2V0cosθ.dt LV00π/3dθcosθ=0Tdt T=LV0.ln(secθ+tanθ)|0π/3 T=LV0ln(2+3)

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