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A robber steals a bag from a man at 5 P.M. and start running at 10 kmph. Police is informed by the man at 12 min past 5 P.M. and the police man chases him on a cycle at 15 kmph. At what time is the robber caught by the police.

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5 : 40 P.M

5 : 12 P.M

5. 36 P.M

5 : 48 P.M.

answer is C.

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Detailed Solution

Robber speed = 10kmph

Police speed = 15 kmph

Robber travelled in 12 min $= 10 \times \frac{12}{60} = 2 k m$

Robber caught by the police $= \frac{2}{(15 - 10)} = \frac{2}{5} h r$

$(\frac{2}{5} \times 60) = 24 \min$

Time $= 5 : 12 + 24 = 5 : 36 p m$

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