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Q.

A rocket fired vertically ascends from rest with a constant acceleration g/3 for 1 min.  Its fuel is then all used and it continues to rise as a free body.  What is the maximum height reached above the ground ?  (g=10  ms−2)

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a

6 km

b

2 km

c

4 km

d

8 km

answer is D.

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Detailed Solution

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0 to A (accelerated motion)
v0=0+a1t1=g3×60=200m/sh1=0+12a1t12=12×g3×(60)2=6000m
A to B (motion under gravity):
0=v02−2a2h2
0=(200)2−2×10×h2=2000m
Maximum height attained by the rocket =h1+h2=8000m

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