A rocket is fired vertically from the ground with a resultant vertical acceleration of $10 m / s^{2}$ . The fuel is finished in 1 min and it continues to move up. What is the maximum height reached?

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25.6 km

36.4 km

42.3 km

48.4 km

answer is C.

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Detailed Solution

$\begin{array}{l} h_{1} = 0 + \frac{1}{2} \times 10 \times 60^{2} = 18 km \\ v_{1} = 0 + 10 \times 60 = 600 m / s \\ h_{2} = \frac{{v_{1}}^{2} - 0}{2 g} = \frac{600^{2}}{2 \times 9.8} = 18.4 km \\ h = h_{1} + h_{2} = 36.4 km \end{array}$

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