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Q.

A rocket is in the form of a right circular cylinder closed at the lower end and surmounted by a cone with the same radius as that of the cylinder. The diameter and height of the cylinder are 6 cm and 12 cm, respectively. If the slant height of the conical portion is 5 cm, what is the total surface area and volume of the rocket respectively? [Use π = 3.14]?


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a

320.44 cm² and 376.8 cm³

b

301.44 cm² and 376.8 cm³

c

353.82 cm² and 376.8 cm³

d

300.44 cm² and 376.8 cm³ 

answer is B.

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Detailed Solution

Given that the diameter of the cylinder is 6 cm, and the height is 12 cm.
Determining the height of the cone:
l 2 = r 2 + h 2 h 2 = l 2 r 2 h 2 = 5 2 3 2  
h 2 =16 h=4  
Let us assume that the volume of the rocket is V, volume of the cylinder be V' and the volume of the cone be V''. So,
V= V + V V=π r 2 H+ 1 3 π r 2 h V=π r 2 H+ 1 3 h V=3.14× 3 2 12+ 1 3 ×4  
V=3.14×120 V=376.8c m 3  
Let us assume that the total surface area of the rocket be S, curved surface area of cylinder be S', curved surface area of cone S'' and area of base of cylinder be S'''. So,
S=S'+S''+S''' S=2πrH+πrl+π r 2 S=πr 2H+l+r S=3.14×3 2×12+5+3  
S=301.44c m 2  
Therefore, 2 is the correct options.
 
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