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Q.

A rod AB of mass m and length l lies on a smooth horizontal surface, end A is pivoted at a fixed point so that the rod can rotate on the horizontal surface about a vertical surface through A. Now particle of mass m moving with velocity v strikes the rod normally at end B and sticks to it. Find the angular velocity of the rod.

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a

3v2l

b

2v3l

c

3v4l

d

4v3l

answer is B.

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Detailed Solution

Conserving angular momentum, 

13ml2+ml2ω=mvl⇒ω=34vl

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