A rod is brought near an uncharged pitch ball electroscope. What conclusion would you draw about the charge on the rod if the pitch ball moves towards the rod?

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Uncharged

Charged

Neutral

Can't say

answer is B.

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Detailed Solution

Concept- A pitch ball is a device used to measure the presence and polarity of charges. The movement of the pitch ball towards the rod is caused by electrostatic induction. To grasp the question, apply the basic principle of attraction of opposite charges and repulsion of like charges.
A pith ball electroscope is a gadget used to determine the polarity of an unknown charge and to learn about static electricity. The charge of a pitch ball can be either positive or negative depending on the charge of the body being used.
As we all know, in electrostatics, charges repel one other while unlike charges attract each other. Like charges denote that both charges are of the same type, but unlike charges denote that one charge must be positive and the other must be negative.
The pitch ball is uncharged in this question. When we approach the pitch ball with a rod, we notice that the pitch ball advances towards the rod. We can conclude that the rod is a charged one. If the rod is made of a negatively charged substance, the electrons within the pitch ball reposition themselves to migrate away from it. This causes a charge imbalance on the pitch ball. Positive charge accumulates on the side closest to the charged rod, while negative charge accumulates on the opposite side. This is the case.
the explanation for the attraction between the rod and the pith ball We can't identify any connections between them here. As a result, there is no actual electron transfer. This is a transient structure known as electrostatic induction. The charged rod causes charges on the pitch ball in this case. When the rod is removed, this temporary arrangement will revert to its original state. When we use a positively charged rod, it induces a negative charge on the pitch ball nearest to the rod. As a result, option 2 is the correct answer.
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