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Q.

A rod length 10cm lies along the principal axis of a concave mirror of focal length ${"mathml":"<math class="image_resized" style="width:36px;height:11px"><span style="font-family:$ in such a way that its end closer to the pole is 20cm away from the mirror. The length of image is:

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a

b

c

d

${"mathml":"<math class="image_resized" style="width:36px;height:11px"><span style="font-family:$

answer is B.(Unlock A.I Detailed Solution for FREE)

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Detailed Solution

Concept- Utilize the mirror equation. The relationship between the mirror's focal length, object distance from the mirror, and image distance from the mirror is provided by this formula. Measure the distances between the rod's two ends and the concave mirror. Then, use the mirror formula to calculate the distances between the rod's two ends and the mirror.Equation used:The mirror equation is provided by

1 f = 1 u + 1 v … … (1)

Mirror equation may be used to determine the position of the image of the closer end to the mirror.

1 v + 1 u = 1 f

⇒ 1 v 1 = 1 − 20 − 1 − 10

⇒ v 2 = − 20

The location of the picture at the opposite end of the mirror is also known as

= 1 v 2 = 1 − (10 + 20) − 1 − 10

⇒ v 2 = − 15

Hence, the length of the image

= 20 cm − 15 cm = 5 cm

Hence, the correct option is 2.

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A rod length 10cm lies along the principal axis of a concave mirror of focal length in such a way that its end closer to the pole is 20cm away from the mirror. The length of image is: