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Q.

A rod of cross sectional area 10 cm2 is placed with its length parallel to a magnetic field of intensity 1000 A/M the flux through the rod is 104webers. Then the permeability of material of rod is

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a

103 wb Am

b

10wb Am

c

104 wb Am

d

102 wb Am

answer is A.

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Detailed Solution

ϕ=BA=μHA⇒μ=ϕHA⋅=104100×10×10−4=104

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