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A rod of length 1.4m and negligible mass has two masses of 0.3kg and 0.7 kg tied to its two ends. Find the location of the point on this rod where the rotational energy is minimum when the rod is rotated about that point

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0.7m from 0.3kg

0.7m from 0.7kg

0.98m from 0.3kg

0.98m from 0.7kg

answer is A.

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Detailed Solution

Rotational KE is minimum about an axis passing through the centre of mass

$r_{1} = \frac{m_{2}}{m_{1} + m_{2}} r = \frac{0.7}{1} \times 1.4 = 0.98$

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