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A rod of length 2m has translational velocity of 0.5ms^-1 in a direction making an angle of 30⁰ with its length. The plane along which the rod is moving is normal to the magnetic field of induction 2T. The emf induced between the ends of the rod ( in volt) is

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Detailed Solution

$\begin{array}{l} θ = 30^{\circ}, B = 2 T \\ e = Bℓvsin θ = 2 \times 2 \times 0.5 \times \frac{1}{2} = 1 V \end{array}$

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