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Q.

A rod of length L is placed along the x-axis with one of its ends at the origin O. The mass of the rod increases linearly as dmdx=λx where λ is a constant. The moment of inertia of rod about an axis passing through its centre of mass and perpendicular to the rod is λL4n. Find n.

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answer is 36.

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Detailed Solution

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xcm=xdmdm=2L3

I=0L(x2L3)2dmI=λL436

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