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A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d-from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is

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a
w(dx)x
b
w(dx)d
c
wxd
d
wdx

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detailed solution

Correct option is B

Since the rod is in equilibrium

So the net torque about B is zero.

τ1=τ2

N1d=w(dx)N1=w(dx)d

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