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Q.

A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d-from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is

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a

wxd

b

wdx

c

w(d−x)d

d

w(d−x)x

answer is B.

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Detailed Solution

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Since the rod is in equilibrium

So the net torque about B is zero.

τ1=τ2

N1d=w(d−x)⇒N1=w(d−x)d

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