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Q.

A rod of weight W is supported by two parallel knife edges A and B is in equilibrium in a horizontal position. The knives are at a dist once d from each other. The center of mass of the rod is at distance x from A. The normal reaction on A is 

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a

W(d−x)x

b

W(d−x)d

c

Wxd

d

Wdx

answer is A.

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Detailed Solution

N1+N2=W⇒N2=W−N1

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Nlx=N2(d−x)⇒Nl(x)=(W−Nl)(d−x)

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