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Q.

A rod with linear charge density $' λ'$ is bent in the shape of a circular ring. The electric potential at the centre of the circular ring is

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a

$\frac{λ}{\in_{0}}$

b

$\frac{λ}{4 \in_{0}}$

c

$\frac{λ}{2 \in_{0}}$

d

$\frac{2 λ}{\in_{0}}$

answer is D.

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Detailed Solution

Potential at the center of the ring

$\frac{Q}{4 π ε_{0} r} = \frac{2 πrλ}{4 π ε_{0} r} = \frac{λ}{2 ε_{0}}$

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