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A rod $1.5 m$ long is placed along the principal axis of a convex mirror of focal length $60 c m$ . The near end of the rod is 1m from the pole of the convex mirror. The length of the image of the rod formed to the nearest integer is ....... cm

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answer is 11.

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Detailed Solution

$f = + 60 c m u_{1} = - 100 c m v_{1} = \frac{600}{16} u_{2} = - 250 c m v_{2} = \frac{1500}{31} I m a g e l e n g t h = |v_{2} - v_{1}|$

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