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Q.

A roller of diameter $6 c m$ rides between two horizontal bars moving in opposite direction as shown in figure. Find the distance of defining the position of the path of the instantaneous centre of rotation of the roller. (Assume no slip at points of contact $P$ and $Q$ )

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a

$4 c m$

b

$3 c m$

c

$2 c m$

d

$1 c m$

answer is C.

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Detailed Solution

Given, diameter $= 6 c m$

$\frac{20}{6 - y} = \frac{10}{y} \Rightarrow 20 y = 10 (6 - y)$

$30 y = 60 \Rightarrow y = 2$

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