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A rope 1 cm in diameter breaks, if the tension in it exceeds 500N. The maximum tension that may be given to similar rope of diameter 3 cm is

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500 N

2000 N

4500 N

3000 N

answer is C.

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Detailed Solution

Breaking stress for both ropes would be same.

$\frac{T_{\max_{1}}}{π \times {(\frac{1}{2})}^{2}} = \frac{T_{\max_{2}}}{π {(\frac{3}{2})}^{2}}$

$\Rightarrow T_{\max_{2}} = 9 \times T_{\max_{1}} = 4500 N$

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