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A rope of length 10 m and linear mass density 4 kg/m is lying lengthwise on a horizontal smooth table. One end of the rope is pulled horizontally by a force of 40 N. The tension in the rope at a point 4 m from point of application of force will be

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24 N

15 N

40 N

49 N

answer is B.

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Detailed Solution

$a = \frac{F}{m} = \frac{40}{40} = 1 m / s^{2}, T = (4 \times 6) \times 1 = 24 N$

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