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Q.

A rope of length 8 m and linear density 0.5 kg/m is lying lengthwise on a horizontal smooth floor. It is pulled by a force of 12 N. The tension at the mid-point would be:

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a

8 N

b

6 N

c

12 N

d

4 N

answer is C.

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Detailed Solution

Mass of the rope $= 8 \times 0.5 = 4 kg$

Acceleration $= \frac{F}{m} = \frac{12}{d} = 3 {ms}^{- 2}$

Mass upto 4 m or mid-point = 2 kg

Force used to pull $2 kg = 2 \times 3 = 6 N$

So, tension at the mid-point = 6 N.

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