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Q.

A rope of negligible mass is wound around a hollow cylinder of mass 3 kg and radius 40cm. If the rope is pulled with a force of 30N, then the angular acceleration produced in the cylinder is

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a

20 rad S–2

b

15 rad S–2

c

25 rad S–2

d

30 rad S–2

answer is C.

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Detailed Solution

Torque = Iα = F x r 

For Hollow cylinder I = Mr2

∴Mr2α=F x t

⇒α=FMr

=303 x 40 x 10-2=1004=25rad/s2

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