A rope of rubber of density 1.5 x 103 Kg/m3 and Young’s modulus 5 x 106 N/m2, 8m in length is hung from the ceiling of a room. Then the increase in length due to its own weight is (g=10m/s2)

Elongation due to its own weight e=MgAl/2Y=lAdgAYl2 e=l2dg2y =64×1.5×103×102×5×106 =96×10−3m

A rope of rubber of density 1.5 x 103 Kg/m3 and Young’s modulus 5 x 106 N/m2, 8m in length is hung from the ceiling of a room. Then the increase in length due to its own weight is (g=10m/s2)

Elongation due to its own weight e=MgAl/2Y=lAdgAYl2 e=l2dg2y =64×1.5×103×102×5×106 =96×10−3m

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A rope of rubber of density 1.5 x 10³ Kg/m³ and Young’s modulus 5 x 10⁶ N/m², 8m in length is hung from the ceiling of a room. Then the increase in length due to its own weight is (g=10m/s²)

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12 x 10^-3 m

96 x 10^-2 m

12 x 10^-4 m

96 x 10^-3 m

answer is C.

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$Elongation due to its own weight e = \frac{Mg}{A} \frac{(l / 2)}{Y} = \frac{lAdg}{AY} \frac{l}{2} e = \frac{l^{2} dg}{2 y} = \frac{64 \times 1 .5 \times 10^{3} \times 10}{2 \times 5 \times 10^{6}} = 96 \times 10^{- 3} m$

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A rope of rubber of density 1.5 x 103 Kg/m3 and Young’s modulus 5 x 106 N/m2, 8m in length is hung from the ceiling of a room. Then the increase in length due to its own weight is (g=10m/s2)

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A rope of rubber of density 1.5 x 10³ Kg/m³ and Young’s modulus 5 x 10⁶ N/m², 8m in length is hung from the ceiling of a room. Then the increase in length due to its own weight is (g=10m/s²)