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Q.

A rope whose mass supports a block of mass three times that of rope. A pulse is generated in string near lower end. The pulse moves up with acceleration in $m / s 2$

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answer is 5.

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Detailed Solution

$v^{2} = \frac{T}{μ} = \frac{(L + μ x) g}{μ} = \frac{M g}{μ} + g x$

$a = v \frac{d y}{d x} = \frac{g}{2} = 5 m / s^{2}$

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