A round table conference is to be held between 20 delegates of 2 countries. In how many ways can they be seated if two particular delegates are always together

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$20!$

$18!$

$2!$

$18! \times 2!$

answer is D.

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Detailed Solution

Two particular delegates can be considered as a person then there are $18 + 1 = 19$ persons, they can be arranged around a circle in 18! Ways and particular persons can be arranged in 2! Ways.

Thus total $= 18! \times 2!$ .

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