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A round uniform body of radius R, mass M and moment of inertia I rolls down (without slipping) an inclined plane making an angle $θ$ with the horizontal. Then its acceleration is

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$\frac{g \sin θ}{1 - I / {MR}^{2}}$

$\frac{g \sin θ}{1 + I / {MR}^{2}}$

$\frac{g \sin θ}{1 + {MR}^{2} / I}$

$\frac{g \sin θ}{1 - {MR}^{2} / I}$

answer is B.

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Detailed Solution

From Equation $a = \frac{g \sin θ}{1 + k^{2} / R^{2}} a = \frac{g \sin θ}{1 + {Mk}^{2} / {MR}^{2}}$

$= \frac{g \sin θ}{1 + I / {MR}^{2}}$

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