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Q.
A rubber ball is released from a height of 5 m above the floor. It bounces back repeatedly, always rising to 81/100 of the height through which it falls. Find the average speed of the ball. (Take g=10 ms−2 )
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b
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answer is B.
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Detailed Solution
The rubber ball is released from a height of 5 meters and bounces back to 81% of the height from which it falls. We will calculate the average speed of the ball using the following steps:
1. Calculate the initial velocity upon release:
The velocity with which the ball strikes the ground is determined by the equation:
v = √(2gh)
Where: g = 10 m/s² (acceleration due to gravity) and h = 5 meters (initial height).
Substituting the values:
v = √(2 × 10 × 5) = 10.0 m/s
2. Determine the rebound height after the first bounce:
The ball rebounds to 81% of the height from which it fell:
h₁ = 0.81 × h = 0.81 × 5 = 4.05 meters
3. Calculate the time taken for the initial fall and subsequent bounces:
The time to fall from a height h is given by:
t = √(2h/g)
For the initial fall:
t₀ = √(2 × 5 / 10) = 1 second
For the first bounce:
t₁ = √(2 × 4.05 / 10) ≈ 0.9 seconds
The time for each subsequent bounce decreases by a factor of √(0.81) due to the 81% rebound height.
4. Calculate the total distance traveled:
The total distance includes the initial fall and the sum of all subsequent bounces. Using the formula for an infinite geometric series:
Total Distance = h + 2 × (h₁ + h₂ + h₃ + ...)
Using the sum of the infinite geometric series with the first term h₁ = 4.05 meters and common ratio r = 0.81, we get:
Sum = h₁ / (1 - r) = 4.05 / (1 - 0.81) = 21.3684 meters
Therefore, the total distance is:
Total Distance = 5 + 2 × 21.3684 = 47.7368 meters
5. Calculate the total time taken:
The total time is the sum of the times for the initial fall and all subsequent bounces:
Total Time = t₀ + 2 × (t₁ + t₂ + t₃ + ...)
Using the sum of the infinite geometric series with the first term t₁ = 0.9 seconds and common ratio r = √(0.81), we get:
Sum = t₁ / (1 - r) = 0.9 / (1 - 0.9) = 9 seconds
Therefore, the total time is:
Total Time = 1 + 2 × 9 = 19 seconds
6. Calculate the average speed:
The average speed is the total distance divided by the total time:
Average Speed = Total Distance / Total Time = 47.7368 / 19 ≈ 2.51 m/s
Final Answer
The average speed of the ball is approximately 2.5 m/s. Therefore, the correct option is:
b) 2.50 m/s