Q.

A rubber ball of mass m and radius R is filled with air. The excess pressure inside the ball is ΔP. However, mass of the air in the ball is negligible. The ball surface is flexible but non-stretchable. When you push its surface at a point with your finger, the ball’s surface in contact with your finger gets flattened as a circle of area A. In this position, the ball exerts a force ΔPA on your finger. We will assume that when A is small, the excess pressure remains unchanged. Such a ball strikes a vertical wall when moving horizontally and rebounds with its speed unchanged. The ball remained in contact with the wall for a time interval Δt. Assume the deformation in the ball to remain small.

Question Image

Contact area between the finger and the surface of the ball is A. Force between them is ΔPA. 

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

By conceptual
Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon