A salt solution gives white ppt with $N H_{4} C l + N H_{4} O H + H_{2} S$ . If drops of $N a O H$ are added to this salt solution a dirty white ppt is formed which dissolves in excess of NaOH. The cation present in the salt is

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$C a^{2 +}$

$F e^{+ 3}$

$Z n^{2 +}$

$P b^{2 +}$

answer is C.

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Detailed Solution

$Z n^{2 +} \overset{N H_{4} C l + N H_{4} O H + H_{2} S}{\to} Z n S ↓ (w h i t e)$
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$N a_{2} Z n O_{2} (o r) N a_{2} [Z n {(O H)}_{4}]$ ……sodium zincate

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