A sample of 100 litre pond water required to oxidise entire organic matter is 200 ml of 1MK2Cr207 (50% H2S04). What COD(Chemical Oxygen Demand) of water

1 mole K2Cr2O7 liberates 48 g of oxygen0.2 mole K2Cr2O7 liberates → ?=0.2×48g=9.6gPPM=9.6g105g×106=96

A sample of 100 litre pond water required to oxidise entire organic matter is 200 ml of 1MK2Cr207 (50% H2S04). What COD(Chemical Oxygen Demand) of water

1 mole K2Cr2O7 liberates 48 g of oxygen0.2 mole K2Cr2O7 liberates → ?=0.2×48g=9.6gPPM=9.6g105g×106=96

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A sample of 100 litre pond water required to oxidise entire organic matter is 200 ml of 1MK₂Cr₂0₇ (50% H₂S0₄). What COD(Chemical Oxygen Demand) of water

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1 mole $K_{2} {Cr}_{2} O_{7}$ liberates 48 g of oxygen
0.2 mole $K_{2} {Cr}_{2} O_{7}$ liberates $\to$ ?
$\begin{array}{l} = 0 .2 \times 48 g = 9 .6 g \\ PPM = \frac{9 .6 g}{10^{5} g} \times 10^{6} = 96 \end{array}$

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A sample of 100 litre pond water required to oxidise entire organic matter is 200 ml of 1MK2Cr207 (50% H2S04). What COD(Chemical Oxygen Demand) of water

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A sample of 100 litre pond water required to oxidise entire organic matter is 200 ml of 1MK₂Cr₂0₇ (50% H₂S0₄). What COD(Chemical Oxygen Demand) of water