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Q.

A sample of a hydrate of barium chloride weighing 61 g was heated until all the water of hydration is removed. The dried sample weighed 52 g. The formula of the hydrated salt 'is : (atomic mass. Ba= 137 amu, Cl= 35.5 amu)

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a

${BaCl}_{2} \cdot 4 H_{2} O$

b

${BaCl}_{2} \cdot 2 H_{2} O$

c

${BaCl}_{2} \cdot 3 H_{2} O$

d

${BaCl}_{2} \cdot H_{2} O$

answer is A.

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Detailed Solution

For, ${BaCl}_{2}, n = \frac{52}{208} = \frac{1}{4}$

For, $H_{2} O, n = \frac{9}{18} = \frac{1}{2}$

$\Rightarrow {BaCl}_{2} \cdot 2 H_{2} O$

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A sample of a hydrate of barium chloride weighing 61 g was heated until all the water of hydration is removed. The dried sample weighed 52 g. The formula of the hydrated salt 'is : (atomic mass. Ba= 137 amu, Cl= 35.5 amu)