A sample of a metal oxide has formula $M_{0.83} O_{1.00}$ . The metal M can exist in two oxidation states +2 and +3. In the sample of $M_{0.83} O_{1.00}$ , the percentage of metal ions existing in +2 oxidation state is _____%. (nearest integer)

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Detailed Solution

Let no. of $M^{+ 2} ions = x$
$\begin{array}{l} ∴ no. of M^{+ 3} ions = 0.83 - x \\ x (+ 2) + (0.83 - x) (+ 3) = 2 \end{array}$
$% of M^{+ 2} ions = \frac{no.of M^{+ 2} ions}{0.83} \times 100$

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