A sample of adulterated milk has a density of 1032 kg/m3 while pure milk has a density of 1080 kg/m3. Then the volume of pure milk in a sample of 10L of adulterated milk is:

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0.5L

answer is D.

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Detailed Solution

Concept- Relationship between mass, volume and density.
Starting with finding the mass of 10L of adulterated milk, we get it as:
1L = 10-3m3.
Given the density of the milk, from this we find the mass of it
So, the mass will be 1032

×

10-3m3= 10.32kg
We know that mass is density x volume. Given in the question we see that some mass of water is added to milk to form adulterated milk. Now, the volume of water is equal to the volume of pure milk. Now, the mass of pure milk can be written as 1080 x M(pure milk)
So,
80 V(p) = 0.32
V(p) = 0.004 m3.
Hence, the density will be 4L.
Hence, the correct answer. is option 4.

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