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A sample of aqueous ${CuSO}_{4}$ was divided into two equal parts. Through one of these, $H_{2} S$ gas was passed and through the other a small amount of dilute ${NH}_{3}$ solution was added. The colour of the precipitates formed in these two cases will be respectively

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Bluish-White and Black

Black and Brown

Brown and Black

Black and Bluish-white

answer is D.

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Detailed Solution

${CuSO}_{4 (aq)} + H_{2} S_{(g)} \to \underset{Buck}{CuS} ↓ + H_{2} {SO}_{4 (aq)}$
${CuSO}_{4 (aq)} + 2 {NH}_{4} {OH}_{(aq)} \to \underset{\underset{Whis}{Btigh}}{Cu (OH)_{2}} ↓ + {({NH}_{4})}_{2} {SO}_{4}$

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