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A sample of calcium carbonate (CaCO₃) has the following percentage composition: Ca = 40%; C= 12%; O=48%, If the law of constant proportions is true, then the weight of calcium in 4 g of a sample of calcium carbonate from another source will be

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0.016 g

0.16 g

1.6 g

16 g.

answer is C.

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Detailed Solution

In 100 g CaCO₃, 40 g Ca is present.

In 4 g CaCO₃, Let x g Ca be present

$\frac{x}{4} = \frac{40}{100}$

⟹x=1.6 g

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