A sample of chalk $(C a C O_{3})$ is contaminated with calcium sulphate $(C a S O_{4})$ ; 1 gm of the solid mixture is dissolved in 230mL of N/10 HCl.40mL of N/10 NaOH solution is required to neutralise the excess of acid. The percentage of chalk in the mixture is.

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95%

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answer is A.

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Detailed Solution

Meq of $C a C O_{3} = (230 \times \frac{1}{10} - 40 \times \frac{1}{10}) = 19$ $W_{C a C O_{3}} = \frac{19}{100} \times \frac{100}{2} = 0.95 g$

% Of $C a C O_{3}$ in mixture = $\frac{0.95}{1} \times 100 = 95 %$

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