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Q.

A sample of clay contains 50% silica and 10% water. The sample is partially dried by which it loses 8 gm water. If the percentage of silica in the partially dried clay is 52, what is the percentage of water in the partially dried clay?

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a

2.4%

b

2.0 %

c

6.4%

d

10.4%

answer is B.

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Detailed Solution

50%SiO2,10%H2O,40% others

 50→52⇒40→5250×40=41.6

SiO2+ others= 93.6

∴H2O present =100−93.6

                                 = 6.4 %

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