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A sample of gas at 0°C and 1.00 atm pressure occupies 3.00 L. What change in temperature is necessary to adjust the pressure of that gas to 1.5 atm after it has been transferred to a 2.00 L container?

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273°C

0°C

5°C

10°C

answer is B.

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Detailed Solution

$\frac{p_{1} V_{1}}{T_{1}} = \frac{p_{2} V_{2}}{T_{2}}, \frac{1 \times 3}{273} = \frac{1 .5 \times 2}{T_{2}} T_{2} = 273 K Hence, no change is required, i . e . 0 ° .$

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