A sample of gas at constant temperature occupies 95 cm3 under a pressure of9.962 × 104 Nm2. At the same temperature, its volume at a pressure of 10.13 × 104 Nm2 is

V1= 95 ml = 0.095 L Pressure (P1)= 9.962×104 Nm2 It is given that the the Temperature remains same i.e. T1=T2 Pressure (P2)= 10.13 × 104 Nm2 We need to calculate the volume at Pressure (P2) V2= ? We know, P1V1 =P2V2 subsituting the values - 9.962×104×95 =×V2 V2= 9.962×104×95 10.13 × 10 V2 = 93.42 cm3 ⇒V2=93 cm3

A sample of gas at constant temperature occupies 95 cm3 under a pressure of9.962 × 104 Nm2. At the same temperature, its volume at a pressure of 10.13 × 104 Nm2 is

V1= 95 ml = 0.095 L Pressure (P1)= 9.962×104 Nm2 It is given that the the Temperature remains same i.e. T1=T2 Pressure (P2)= 10.13 × 104 Nm2 We need to calculate the volume at Pressure (P2) V2= ? We know, P1V1 =P2V2 subsituting the values - 9.962×104×95 =×V2 V2= 9.962×104×95 10.13 × 10 V2 = 93.42 cm3 ⇒V2=93 cm3

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A sample of gas at constant temperature occupies $95 c m^{3}$ under a pressure of $9.962 \times 10^{4} \frac{N}{m^{2} .}$ At the same temperature, its volume at a pressure of $10.13 \times 10^{4} \frac{N}{m^{2}}$ is

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Detailed Solution

$V_{1} = 95 m l = 0.095 L P r e s s u r e (P_{1}) = 9.962 \times 10^{4} \frac{N}{m^{2}} I t i s g i v e n t h a t t h e t h e T e m p e r a t u r e r e m a i n s s a m e i . e . [T_{1} = T_{2}] P r e s s u r e (P_{2}) = 10.13 \times 10^{4} \frac{N}{m^{2}} W e n e e d t o c a l c u l a t e t h e v o l u m e a t P r e s s u r e (P_{2}) V_{2} = ? W e k n o w, P_{1} V_{1} = P_{2} V_{2} s u b s i t u t i n g t h e v a l u e s - 9.962 \times 10^{4} \times 95 = \times V_{2} V_{2} = \frac{9.962 \times 10^{4} \times 95}{10.13 \times 10} V_{2} = 93.42 c m^{3} \Rightarrow V_{2} = 93 c m^{3}$