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Q.

A sample of hard water contains 0.005 mole of CaCl2 per litre. What is the minimum concentration of Na2SO4 (in mole/ L)which must be exceeded for removing Ca2+ ions from this water sample? The solubility product of CaSO4 at 25° C is 2.4 x 10-5 • (Give your answer after multiplying with 10000 and· excluding any decimal places)

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answer is 48.

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Detailed Solution

Here, we know that,

Ca2+×SO42−=Ksp

Put the values,

5×10−3×SO42−=2.4×10−5⇒ SO42−=48×10−3

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