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Q.

A sample of hydrate of barium chloride weighing 122 g was heated until all the water  of hydration is removed. The dried sample weighed 104g. The formula of the hydrated salt is BaCl2.xH2O . Then x = ?

 (atomic mass, Ba = 137 amu, Cl = 35.5 amu) 

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answer is 2.

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Detailed Solution

 BaCl2.xH2OABaCl2+xH2O
122g of  BaCl2.xH2O upon heating loses = 122-104 = 18 g
M.wt  of   BaCl2= 208 g
104g of barium chloride contains   18 g
20 g of barium chloride contains   ? = 36 g
  No. of H2O  molecule =  3618=2
 BaCl2.2H2O

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