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Q.

A sample of hydrate of barium chloride weighing 122 g was heated until all the water of hydration is removed. The dried sample weighed 104g. The formula of the hydrated salt is $B a C l_{2} . x H_{2} O$ . Then x = ?
(atomic mass, Ba = 137 amu, Cl = 35.5 amu)

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answer is 2.

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Detailed Solution

$B a C l_{2} . x H_{2} O \overset{A}{\to} B a C l_{2} + x H_{2} O$
122g of $B a C l_{2} . x H_{2} O$ upon heating loses = 122-104 = 18 g
M.wt of $B a C l_{2}$ = 208 g
104g of barium chloride contains $\to$ 18 g
20 g of barium chloride contains $\to$ ? = 36 g
No. of $H_{2} O$ molecule = $\frac{36}{18} = 2$
$B a C l_{2} .2 H_{2} O$

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