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A sample of impure silver (1.5g) is heated with sulphur to form ${Ag}_{2} S .$ The mass of ${Ag}_{2} S .$ formed was 0.124g. The percent yield of silver sulphide is

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6.41%

7.2%

8.27%

10.8%

answer is B.

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Detailed Solution

$2 Ag + S \to {Ag}_{2} S$

$2 \times 107.87 g - - 247.74 g of {Ag}_{2} S$

215.74 g ––– 247.74 g

1.5 g ––– ?

$\frac{1.5}{215.74} \times 247.74 = 1.72 g m$

$% yeild = \frac{0.124}{1.722} \times 100 = 7.200 %$

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