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Q.

A sample of iron ore contains FeS and non-volatile inert impurity only. Roasting of this ore converts all iron in FeS into Fe2O3 and a 3.6% loss in weight was observed. The mass percentage of FeS in the given sample of ore is (Fe =56 g/mol, S=32 g/mol, O=16 g/mol).

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answer is 39.6.

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Detailed Solution

Let weight of FeS =Xg, weight of impurity = (100−x)g

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∴ final weight : 10X11+(100−X)=96.4, X=39.6 g

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